I am dealing with it lol. Give me the money XD.

No need to translate it, just scroll down and read the comic. Really funny/kind of creepy stuff!

http://comic.naver.com/webtoon/detai...31&weekday=tue

OMFG WHEN THE WOMEN LOOKED BACK.
Omg i almost pissed myself...

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO OOOOOOoooooooooooooooooooooooooooooooooooooooooooo ooooo!!!!


not this comic god damn....i've jumped from my bed and fell on the ground -.-
rly thank you....

Toon, your statement is wrong.

x isn't equals 3.

Here is the solution :
12-2/3x = 1e
12-2/3x = e
12-2/3x = 12-2/3x
(12-2/3x)/x = 12-2/3
12-2/3 = 12-2/3
(36-2)/3 = (36-2)/3
34/3 = 34/3

So x = ]-∞;+∞[ excluding 0

Same thing goes for e.

That is a system of 1 equation with 2 unknowns. Every equation containing 2 unknowns has it's unknowns varying between -∞ and +∞
That's why we said it's unsolvable, since we can never know the exact number, because the equation will always be valid with both x and e varying between -∞ and +∞, but of course, in this case, x has to be =/= than 0 cause the denominator cannot be 0 else the fraction would become an ∞ as well.

To get the exact number, the system has to be of 2 equations with 2 unknowns.

I'm back! :P Still don't know who unbanned me, but I am grateful anyway.

EDIT: Link, I need to go back to my position :P I tried promoting myself with Pube but all it did was refresh the page.

HAHA this is a day to celebrate
Hip Hip Hooraay
join the party

http://www.algebra.com/algebra/homew...ion.52970.html

Not correct here is my proof fool!

E is 10! what is 10x1?
Thats my proof deal with it in therapy if you got a problem with it. ;p

What?

In the question you told us, e was an unknown, the link you put is an equation with one unknown, but the question was with 2 unknowns.

That's not math, that's a trick. :3

But it worked now didn't it. ;p