Toribash
Me and beggy have done some quite similar stuff that SHOULD NOT BE SHARED WITH ANYONE too. XD
Your messed up world enthrills me
Sold Demon force for 80k. Probably did some profit since I actually bought it for 30k+pure force+daimyo hat= 30+16+10=56k
80k-56k= 24k ...not so bad. Could have sold it for like 10k more I guess.

Didn't fit the set at all. I reverted back to cobra relax+pure force. What a great combo!
Your messed up world enthrills me
Could anyone be a sweetie and help me solve this? :* I just can't get it right.

Solve: 1/2y-1 + 1/1+2y - 1/y+2 = 0
Siku can't touch this!
it should end up in y=-0,125 ( 1/8 )

Nvm, got it :>

Answer if anyone is interested

Last edited by swedishpower; Nov 26, 2013 at 07:25 PM.
Siku can't touch this!
Originally Posted by Shockey911 View Post
Thats some good marketing Willy, but you should try getting raider and pure or some sore of darker blue. It looks nice

I have raider :P

It's not really good marketing..the guy who gave me the demon relax was pretty desperate and I was just lucky. :P
Last edited by William; Nov 26, 2013 at 08:18 PM. Reason: <24 hour edit/bump
Your messed up world enthrills me
Originally Posted by William View Post
I have raider :P

It's not really good marketing..the guy who gave me the demon relax was pretty desperate and I was just lucky. :P

Thats the people you aim for, The desperate people!

Also: I made something. I dont know if its good or not, seems good to me. cnc maybe?

http://oi39.tinypic.com/34oyhcg.jpg
Last edited by Shockey; Nov 26, 2013 at 10:38 PM.
Simplifying expressions, lets consider this one:

1/(2y-1) + 1/(1+2y) - 1/(y+2) = 0
——————————————————


Okay, so the problem is the multiple denominators here; so lets get rid of those,
but first we rearrange it so that we do not work with a 0 on the rhs:

As we add 1/(y+2) to both sides:

(1/(2y-1) + 1/(1+2y) - 1/(y+2)) + 1/(y+2) = (0) + 1/(y+2) <=>
1/(2y-1) + 1/(1+2y) = 1/(y+2) <=>

Getting rid of the left hand denominator by multiplying both sides with (y+2) gives:

(y+2)(1/(2y-1) + 1/(1+2y)) = (y+2)(1/(y+2)) <=>
(y+2)/(2y-1) + (y+2)/(1+2y) = 1 <=>

Now lets get rid of another by directly multiplying with (1+2y) on both sides:

(1+2y)((y+2)/(2y-1) + (y+2)/(1+2y)) = (1+2y)1 <=>
(1+2y)(y+2)/(2y-1) + (y+2) = (1+2y) <=>

Same story with the (2y-1):

(2y-1) ((1+2y)(y+2)/(2y-1) + (y+2)) = (2y-1)(1+2y) <=>
(1+2y)(y+2) + (y+2)(2y-1) = (1+2y)(2y-1) <=>

Lets have it equal 0 and make teachers happy!

(1+2y)(y+2) + (y+2)(2y-1) - (1+2y)(2y-1) = 0 <=>

Expanding it:

(y + 2 + 2yy + 4y) + (2yy - y + 4y - 2) - (2y - 1 + 4yy - 2y) = 0 <=>

Cancelling out terms/factors within parentheses:

(2yy + 5y + 2 ) + (2yy + 3y) - (4yy - 1) = 0 <=>

Getting rid of parentheses:

2yy + 5y + 2 + 2yy + 3y - 4yy + 1 = 0 <=>

Cancelling out terms/factors:

8y + 1 = 0 <=>

Rearranging the constants:

8y = -1 <=>

Finally dividing by the factor infront of our variable, in this case y:

y = -1/8

Tada!


And yes, I'm late to the party.
Last edited by Smogard49; Nov 27, 2013 at 12:17 AM. Reason: Damn, k6 were fast as hell to understand that reference...
Now doing recoloring for people not in the clan as-well, PM for more info!
PROUD OWNER OF THORN'S GOOD ENOUGH WRITER AWARD!